Brief Description on 2N Transistor 2N is a NPN transistor hence the collector and emitter will be left open Reverse biased when the base pin is held at ground and will be closed Forward biased when a signal is provided to base pin. The maximum amount of current that could flow through the Collector pin is mA, hence we cannot connect loads that consume more than mA using this transistor. To bias a transistor we have to supply current to base pin, this current IB should be limited to 5mA by using a transistor to the base pin. When this transistor is fully biased then it can allow a maximum of mA to flow across the collector and emitter. This stage is called Saturation Region.
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Mezitaur Here lets us assume the load here consumes around mA maximum so our collector current I C mA. However this vale will not be very accurate because the transistor datazheet have an internal voltage drop across the collector current, so it mostly experimental to get the maximum current from the transistor. The 2N is a NPN transistor and is normally used as a switch in many circuits.
So if you looking for an NPN transistor that could switch loads or for decent amplification then 2N might the right choice for your project. Complete Technical Details can be found at the datasheet given at the end of this page.
To make this current flow through the transistor the value of base current I B can be calculated using the below formula:. Transistor Catalog This resistor is connected to the base pin of the transistor to limit the current flowing through the base.
In our case for a collector current of datsaheet we have to pass a base current of 16mA. Submitted by admin on 21 June Overall it is just another small signal transistor which is commonly used in dtaasheet and amplifying circuits.
Another important thing to keep in mind, while using a transistor as switch is the base resistor. As we know the transistor is a current controlled device meaning, we have pass some current I B thorough the base of the transistor to turn it on. To bias a transistor we have to supply current to base pin, this current I B should be limited to 5mA by using a transistor to the base pin. Where h FE, is the current gain of the transistor which in our case is This stage is called Saturation Region.
So the value if R B will be. To make this current flow through the transistor the value of base current I B can datxsheet calculated using the below formula: Amplifier modules like Audio amplifiers, signal Amplifier etc. The maximum amount of current that could flow through the Collector pin is mA, hence we cannot connect loads that consume more than mA using this transistor.
TL — Programmable Reference Voltage. Since transistor is of NPN the load to be switched should be connected to the ratasheet and the emitter should be connected to the ground as show in the figure below. When base current is removed the transistor becomes fully off, this stage is called as the Cut-off Region and the Base Emitter voltage could be around mV.
When this transistor is fully biased then it can allow a maximum of mA to flow across the collector and emitter. The value of this current can be calculated by the required amount of current that will be consumed by the load. But it comes in a datashee can package and can operate on voltages slightly higher than what a 2N can handle. But this calculation will lead to the closest value to start with.
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